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Mathematics 19 Online
OpenStudy (anonymous):

Is this correct? :D

OpenStudy (anonymous):

OpenStudy (unklerhaukus):

i dont think so

OpenStudy (saifoo.khan):

me either! ;)

OpenStudy (anonymous):

it is 12(tan(45)).

OpenStudy (anonymous):

How? :O Because when I do that I get 12, and it cant be the length of 12

OpenStudy (anonymous):

It should be 12(tan(45)) because the formula for cos is: \[\cos(\theta) = \left(\begin{matrix}a \\ h\end{matrix}\right)\] So with this equation there is no way to find the height it is asking for. However, the Tan formula is: \[\tan(\theta) = \left(\begin{matrix}o \\ a\end{matrix}\right)\] So multiplying the adjacent side (12) is going to get you: \[12\tan(45) = o\] And "o" in this case is the opposite side, the height it is asking for.

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