how do i find an equation of the line parrell to 2x + y=7 and through (5,-2)

Question

how do i find an equation of the line parrell to 2x + y=7  and through (5,-2)

experimentx · Answer

your equation is 3x+y = k , where k is a constant to be found
since it passes through 5,-2, put the value there and find the value of k and place the value of k and you have your equation

campbell_st · Answer

the given line in poitn slope form is  y = -2x + 7

the slope of the line is m = -2

then using point slope formula where, m = -2 and (5, -2)

y + 2 = -2x +10

2x + y = 8

experimentx · Answer

looks like k is 8

anonymous · Answer

where did the 2 and 10 come from

anonymous · Answer

Since it's parallel, the new slope would be the same as the new slope, which is -2.
Since you have your new slope and the points (5,-2)
You plug into this linear equation
Y-Y1=M(X-X1)
M=slope=-2
Y1=-2
X1=5
And Y & X just stays like that.

If you plug in the numbers, you should get.
y = -2x+8