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Mathematics 22 Online
OpenStudy (anonymous):

Find P for P=Q+PQ+PQ^2 Where Q is a matrix 2x2 with the numbers [-1 0] in the top row and [5 -2] in the bottom row.

OpenStudy (anonymous):

\[\left[\begin{matrix}-1 & 0 \\ 5 & -2\end{matrix}\right]\] Is the matrix.

OpenStudy (callisto):

PQ^2 or (PQ) ^2 ?

OpenStudy (anonymous):

Just PxQ^2

OpenStudy (callisto):

OpenStudy (callisto):

Sorry very poor handwriting and not in a good state today :(

OpenStudy (anonymous):

Pretty sure that's the answer. Do you know how to do it with inverses? Or is it even possible with them?

OpenStudy (callisto):

you mean finding the inverse of P?

OpenStudy (anonymous):

Sorry, worded that wrong. Can you do it with Matrix algebra?

OpenStudy (callisto):

Sorry, i don't know what matrix algebra is.. :(

OpenStudy (anonymous):

If you had AC=B To get A on it's own you have to pre multiply by the inverse of C since CxC^-1 = I So ACC^-1=BC^-1 A=BC^-1 It's what i'm learning now so i guessed that's how the question had to be answered.

OpenStudy (anonymous):

But if you don't know how to do it like that then it's fine :) thank anyway!

OpenStudy (callisto):

ah... i learnt it.. but gimme some time to think about it...

OpenStudy (anonymous):

Alright cheers :) I tried it but gut it wrong both times :/

OpenStudy (callisto):

that's sth i hate doing in my exam :(

OpenStudy (anonymous):

yeah haha :/

OpenStudy (callisto):

the steps are quite messy... :(

OpenStudy (anonymous):

Thank you! haha :)

OpenStudy (callisto):

nah.. i made a mistake!

OpenStudy (callisto):

not a mistake, but some mistakes :S

OpenStudy (anonymous):

what was it?

OpenStudy (anonymous):

oh alright

OpenStudy (callisto):

the negative sign, i copied the wrong one and just forgot to correct them :'(

OpenStudy (anonymous):

ahh well thanks a lot :)

OpenStudy (callisto):

welcome, glad to help :)

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