Question

SHOWYOURWORK! (2x^2)(-8x^3)
and solve the system of equations 2x-y=-10
3x+4y=1

Answer 1

There's 2 questions there?

Answer 2

(2x^(2))(-8x^(3))

Multiply 2x^(2) by -8x^(3) to get -16x^(5).
-16x^(5)

Answer 3

and then solve the two last eqautions

Answer 4

2x-y=-10..................(1)
3x+4y=1 ...............(2)

From 2x-y=-10,
2x=y-10
x=(y-10)/2
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From (2),
3x+4y=1
3(y-10)/2+4y=1
Multiply each term by a factor of 1 that will equate all the denominators. In this case, all terms need a denominator of 2.
(3(y-10))/(2)+4y*(2)/(2)=1

Multiply 4y by 2 to get 8y.
(3(y-10))/(2)+(8y)/(2)=1

The numerators of expressions that have equal denominators can be combined. In this case, (3(y-10))/(2) and ((8y))/(2) have the same denominator of 2, so the numerators can be combined.
(3(y-10)+(8y))/(2)=1

Combine all similar expressions in the polynomial.
(11y-30)/(2)=1

Multiply each term in the equation by 2.
11y-30=2

move all terms not containing y to the righthand side of the equation.
11y=32

Divide each term in the equation by 11.
y=32/11
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x=(y-10)/2
x=((32/11)-10)/2

y=-(39)/(11)

Answer 5

x=-(39)/(11) , not y