Question

tan^2(180+x) ???

Answer 1

\[\tan^2(180+x) = (\tan(180)+\tan(x))^2/(1-\tan(180) \tan(x))^2\]

Answer 2

x = ?

Answer 3

I'm so cunfused tight now I'm writing tomorrow and I'm stressing profusely :/

Answer 4

kk, take it easy. what's the p ?

Answer 5

Ok (breath) the equation I'm battling with is (cos(180-x)) .(sin(x-90)) - 1 / (tan^2(180+x)).(sin90+x).(cos(-x))

Answer 6

(sin(90+x))*

Answer 7

\[\sin(90+x) = \cos(x) \sin(90)+\cos(90) \sin(x) \]

Answer 8

Ok I got that, If you've got -cos112.sin22- ((cos428.sin(-68))/tan202) how would you make the angles(?) sharp?

Answer 9

sharp ?

Answer 10

Haha I'm so sorry, I'm from S.A so trying to correctly translate these terms are a litte hard

Answer 11

i don't think i still get you, just use a calculator ?

Answer 12

The problem is we have to show our calculations, these problems usually count up to 8-10 marks... just writing down an answer isn't going to help me in this case

Answer 13

and a calculator can't be used ?

Answer 14

Not at all, we have to do our papers without a calculator

Answer 15

kk, do you have a formula book ?

Answer 16

Yes (: I wrote the the test which wasn't to bad should get about 80 =)

Answer 17

kk, God bless!