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Mathematics 7 Online
OpenStudy (anikate):

See Picture. It has to do with circle radius. Please help me. This will be quick.

OpenStudy (anikate):

help

OpenStudy (nottim):

I can't see circle b

OpenStudy (anikate):

You need find the radius of circle b

OpenStudy (unklerhaukus):

\[C_A=3A_B\] \[C=2πr;\quad A=πr^2\] \[C_A=2πr_A;\quad A_b=πr_B^2\] \[2πr_A=3πr_B^2\]

OpenStudy (nottim):

But I can't see it! Is it important!

OpenStudy (anikate):

you make up a circle b n find radius

OpenStudy (unklerhaukus):

\[r_A=27/2\]

OpenStudy (anonymous):

circumference of circle A is \[27\pi\]

OpenStudy (anonymous):

so area of circle B is one third of that, namely \[9\pi\]

OpenStudy (anonymous):

so we know \[9\pi=\pi r^2\]solving for r tells us \[r=3\]

OpenStudy (unklerhaukus):

\[2π\times {27 \over 2}=3πr_B^2\] \[27/3=r_B^2\] \[9=r_B^2\] \[r_B=3\]

OpenStudy (anonymous):

rb=3

OpenStudy (anonymous):

i have to add that this is a very silly and misleading question. the \[27\pi\] is a length, whereas the \[9\pi\] is an area, they live in different dimensions. second one is in square units

OpenStudy (anikate):

y is there a pi symbol after every answer

OpenStudy (anikate):

?

OpenStudy (anonymous):

the radius you are looking for does not inlude the number pi. it is just 3

OpenStudy (anikate):

so the radius of Circle be is?

OpenStudy (anonymous):

3 in

OpenStudy (anonymous):

I meant 3 cm

OpenStudy (anikate):

k and R U EXTREMELY POSSITIVELY SURE!!

OpenStudy (anikate):

I cant afoord to lose points on this QUIZ

OpenStudy (anonymous):

oh hold on..

OpenStudy (anonymous):

yes 99%

OpenStudy (anikate):

it has to be above 101%

OpenStudy (anikate):

y is it not 4.5 cm.

OpenStudy (anikate):

?

OpenStudy (anonymous):

that is imposible.. even einstein could not say that..

OpenStudy (anikate):

what is impossible?

OpenStudy (anonymous):

101%

OpenStudy (anikate):

k fine it must be 100%

OpenStudy (anikate):

now why can't it be 4.5 cm., the radius?

OpenStudy (anonymous):

Is is already solved by unkleraukus at the above..

razor99 (razor99):

do u know the formulae @Anikate

OpenStudy (anikate):

yup

OpenStudy (anikate):

not memorized tho

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