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SOLVE the equation (3x-1)/(x+7) -(1)/(3x+2) = (5-x)/(3x^2+23x+14)
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set (3x^2+23x+14)=(7+x) (2+3x)
why would I do that? When I first saw the problem, I thought that I should clear fractions with a common LCD The common LCD is (3x+2)(x+7) so multiply everything by that. then I got (3x-1)(3x+2)-(x+7)=(5-x) when I foil and combine like terms, setting the entire thing equal to 0, I got: (3x+5)(3x-2)=0 so x= 2/3 and -5/3 That is what I have...not sure if it is correct tho..
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