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Michael takes a multiple-choice test with 5 answer choices for each question. If he randomly answers every question what is his expected score?
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20%
as number of questions approaches infinity.
really depends on how many questions on the test right?
yes, in that case, use nCr ((p)^r)(1-p)^(n-r)
oh right, expected "score" not expected number of correct answers.
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n= questions, r=number of correct, p=probability of correct.
inkyvoyd is right, expected "score" is 20% expected number of correct answer is .2 n if n is the number of questions answered
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