Question

Need help with this one

A) solve 4x^2=8
I think i got this one which is x=√2

B) find the x-intercepts of f(x) 4x^2-8
need help on understanding this one

Answer 1

brconnel, plus or minus sqrt(2)
and,
(sqrt(2),0)
(-sqrt(2),0)

Answer 2

would i use the quadratic equation for the intercepts though?

Answer 3

\[4x^{2}=8\]
divide both sides by 4
\[x^{2}=4\]
\[x=\sqrt{2},x=-\sqrt{2}\]

To find the x-intercepts, you have to set y to 0.
\[4x^{2}-8=0\]
You can use the same results from part 8.
\[x-intercepts\ are\ \left\{ (\sqrt{2},0),(-\sqrt{2},0) \right\}\]

Answer 4

part A, not part 8. sorry

Answer 5

ok cool. Makes sense