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\[\lim_{x \rightarrow 0} (3^{x} -4^{x})/\sqrt{x}\]
L'Hospitals rule
its not working please see!!
why is it not working?
check my work??? \[\lim_{x \rightarrow 0} (x \log3 - xlog2)/(0.5\sqrt{x}) \] now if we again apply it will be 0/0 form
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the derivative of \(\sqrt{x}\) is \(\displaystyle\frac{1}{2\sqrt{x}}\)
thats what i meant...
yess now what to do???
dividing by a fraction...invert and multiply
wow...more than one error here..
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\[\frac{d}{dx}a^x=a^x\ln(a)\]
ohhh yah now get it thanks!!1
\[\lim_{x \rightarrow 0} (3^x \log(3) - 4^x\log(4))2\sqrt{x}\]
=0
thanks!!!
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