Ask your own question, for FREE!
Mathematics 25 Online
OpenStudy (anonymous):

ab + 2b +3a + 6 uhm grouping a term i thinkkkk? (:

OpenStudy (anonymous):

I can't belive I forgot how to do this...thinking...

OpenStudy (mertsj):

Factor b out of the first two terms and then factor 3 out of the last two terms.

OpenStudy (anonymous):

Then you will end up b(a+2)3(a+2)

OpenStudy (anonymous):

lol you sure?

OpenStudy (mertsj):

b(a+2)+3(a+2)

OpenStudy (anonymous):

Yes thanks to Mertsj

OpenStudy (mertsj):

Now you have two terms and they have the common factor a+2 so factor out a+2

OpenStudy (anonymous):

Then don't you put the b and 3 together to become (b+3)(a+2)?

OpenStudy (mertsj):

yes

OpenStudy (anonymous):

So the answer is (b+3)(a+2)

OpenStudy (anonymous):

Do you understand why? :)

OpenStudy (anonymous):

uhm , a little i see how you get it . but i feel so dumb . -_- i have a test tomorrow and i'm scared i'm going to fail!

OpenStudy (anonymous):

No!!! Don't feel dumb! Sometimes school is difficult but God can help you with the test. I will pray do you do good. :) Anymore questions? :)

OpenStudy (anonymous):

Then try factoring this (x^2-10x+25)

OpenStudy (anonymous):

Hello?

OpenStudy (anonymous):

Lol! I guess they left. :D

OpenStudy (anonymous):

:P

OpenStudy (anonymous):

O well see ya. :D

OpenStudy (anonymous):

im hereeee

OpenStudy (anonymous):

im trying to figure it out haha

OpenStudy (anonymous):

Oh..!! Lol! Sorry! :D

OpenStudy (anonymous):

(x-5)(x-5) ?

OpenStudy (anonymous):

Well it isn't that hard you know It just needs lots of pratice

OpenStudy (anonymous):

Your missing something...

OpenStudy (anonymous):

It is correct but not complete

OpenStudy (anonymous):

(x-5)+(x-5) ?

OpenStudy (anonymous):

Nope

OpenStudy (anonymous):

uhhmmmmmmmmmmmmmm i don't know :c

OpenStudy (anonymous):

Give up?

OpenStudy (anonymous):

lol yes .

OpenStudy (anonymous):

It is (x-5)^2

OpenStudy (anonymous):

how!?

OpenStudy (anonymous):

Well both are commons

OpenStudy (anonymous):

oh that's truee. here i have another question please come help?

OpenStudy (anonymous):

ok

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!