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i need to find the vertex of x^2+8x+7
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Do you know some calculus?
no im in algebra 1
In that case, start by factoring that polynomial. Can you do that?
yes i got -1 and -7
Now, what is the point between \(-1\) and \(-7\)?
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what do you mean?
As soon as you find the two roots, you need to find the midpoint of the segment \([-7,-1]\).
is it the remaining 8 ?
\[\frac{-7+-1}{2}=-4\]
so you start at the negative four?
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You know that the vertex of the parabola has an \(x\)-value of \(-4\). What is the \(y\)-value?
-9
That is correct.
Using calculus, you can just differentiate:\[2x+8=0\implies x=-4\implies y=-9.\]
so you mark the point on the graph (-4,-9) ?
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That's correct. :)
thank you
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