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Mathematics 21 Online
OpenStudy (anonymous):

i need to find the vertex of x^2+8x+7

OpenStudy (across):

Do you know some calculus?

OpenStudy (anonymous):

no im in algebra 1

OpenStudy (across):

In that case, start by factoring that polynomial. Can you do that?

OpenStudy (anonymous):

yes i got -1 and -7

OpenStudy (across):

Now, what is the point between \(-1\) and \(-7\)?

OpenStudy (anonymous):

what do you mean?

OpenStudy (across):

As soon as you find the two roots, you need to find the midpoint of the segment \([-7,-1]\).

OpenStudy (anonymous):

is it the remaining 8 ?

OpenStudy (across):

\[\frac{-7+-1}{2}=-4\]

OpenStudy (anonymous):

so you start at the negative four?

OpenStudy (across):

You know that the vertex of the parabola has an \(x\)-value of \(-4\). What is the \(y\)-value?

OpenStudy (anonymous):

-9

OpenStudy (across):

That is correct.

OpenStudy (across):

Using calculus, you can just differentiate:\[2x+8=0\implies x=-4\implies y=-9.\]

OpenStudy (anonymous):

so you mark the point on the graph (-4,-9) ?

OpenStudy (across):

That's correct. :)

OpenStudy (anonymous):

thank you

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