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What is the sum of half + 3 quarters + 7 eights +15 sixteenths + 31 thirtytwoths + 63 sixtyfourths + 127 one-two-eighths + 255 two-five-sixths?
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\[\frac{1}{2}+\frac{3}{4}+\frac{7}{8} +\frac{15}{16} +\frac{31}{32} +\text{ }\frac{63}{64}+\frac{127}{128} +\frac{255}{256}=\frac{1793}{256}=7\frac{1}{256} \]
nice robtobey, you did it first. . . :-)
Thank you for the medal.
\[1/2+3/4+7/8+15/16+31/32+63/64+127/128+256/256\]You know, you could have just said\[\sum_{n=1}^{8}(2^{n}-1)/2^{n}\] but yeah the answer would be 1793/256
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