Question

Double checking work here.
Solve
15x^4-14x^2+3=0
My answers are
\[1/\sqrt{3}, - 1/\sqrt{3}\]
\[\sqrt{3/5}, -\sqrt{3/5}\]

Answer 1

the last two are right the first two will be sqrt3 and -sqrt3

Answer 2

so i towuld be \[\sqrt{3}, -\sqrt{3}\] for the first two

Answer 3

yes exactly... re do it... at the factor (x^2-3)=0, i guess u made a mistake.

Answer 4

yea i think i messed up the fraction, inverted them probably on accident

Answer 5

no i actually double checked and the first part ± \[\sqrt{1/3}\]

Answer 6

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