Mathematics
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OpenStudy (anonymous):
How do you do this ?
Solve the equation: 4x2 = 36
A. {6, -6}
B. {3, -3}
C. {2/3, -2/3}
D. {3/2, -3/2}
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OpenStudy (callisto):
4x2 = 36
4x2 -36 =0
Factorise it, put each factor =0, and solve it, try ~
OpenStudy (anonymous):
B
OpenStudy (anonymous):
so 6,-6 ?
OpenStudy (callisto):
you also can take out the common factor first... i meant the '4'
OpenStudy (callisto):
nope..
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OpenStudy (callisto):
factorise 4x2 -36 first
OpenStudy (anonymous):
so i need to find the GCF of 36 ?
OpenStudy (callisto):
36 and 4x^2
OpenStudy (anonymous):
4 .
OpenStudy (anonymous):
is the GCF
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OpenStudy (callisto):
yes.. so you can rewrite it into 4(x^2-9), so now, factorise (x^2 -9)
OpenStudy (anonymous):
2/3 ?
OpenStudy (callisto):
nope...
OpenStudy (callisto):
factorise (x^2 -9)
OpenStudy (anonymous):
thats what i got. its either that or 3/2
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OpenStudy (callisto):
\[x^2 -9 = (x-3)(x+3)\]
OpenStudy (anonymous):
so So if i do the square root of nine and times the answer two times that will give me my answer ?
OpenStudy (callisto):
4x2 -36 =0
4(x^2 -9) =0
4(x+3)(x-3) =0
(x+3)(x-3) =0
x+3 =0 or x-3 =0
x=-3 or x=3
OpenStudy (callisto):
no, \[\sqrt{9} \times 2 = 3\times2 = 6\]
OpenStudy (anonymous):
ok
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OpenStudy (callisto):
do you understand?
OpenStudy (anonymous):
yes