Question

Who's up for a cute problem ?

Answer 1

M*E=ME
:D

Answer 2

give your best young one >:)))

Answer 3

i mean bring out your worst, young one >:))

Answer 4

Okay lets start with a easy one,

If \(a^2,b^2 ,c^2 \) are in arithmetic progression can you show that \( \frac{a}{b+c},\frac{b}{a+c},\frac{c}{a+b} \) are also in A.P

Answer 5

T_1=a^2
T_2=a^2+(1)(d)=b^2
T_3=a^2+2(d)=c^2

Answer 6

fool i have a cute problem too: http://openstudy.com/study#/updates/4f6db95de4b0772daa08442f

Answer 7

Im stucked lol

Answer 8

arithmetic progression...is that the an = a1 + (n-1)d thingy?

Answer 9

yeah thats the genral formula

Answer 10

I have one to Law.
http://openstudy.com/study?login#/updates/4f6db9a5e4b0772daa08443c

Answer 11

Is it like this? (Poor presentation sorry)