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You are given functions f and g such that f(n)=O(g(n)). Is f(n)∗log2(f(n)c)=O(g(n)∗log2(g(n))) ? (Here c is some constant >0. You can assume that f and g are always bigger than 1. a) true b)false c)depends on c d) depends on f and g
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f(n)∗log2(f(n)c) = O(g(n))∗log2(O(g(n))c)
\[f(n)∗\log_{2} (f(n)^{c})=O(g(n)∗\log_{2} (g(n))) ?\]
hey sorry, it was this, and false is wrong answer
i guess the same
option b and c is wrong
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