For the simple harmonic motion equation d=2 sin (pi/3 t), what is the maximum displacement from the equilibrium position? is it 2?
yeah...!! cause the '2' in the equation there represents the amplitude. what do you think that means?? maximum displacement from mean position! Right-O!!
yes, it is. here's something to think about: the function sin(x) is never bigger than 1, no matter what number you choose to plug into it. therefore the maximum value of the equation d= 2sin(x) is 2.
yes, that is the maximum value possible from that equation, since sin(any value) <= 1
Thanks! :)
The equation is d = A sin ( ωt ) ; where A is the amplitude (that is : maximum displacement from the equilibrium position) ; So d = A = 2 ( maximum displacement ) and its + or - is the position relative to equilibrium , when sin ωt = ±1 ==> t = 3( 2k+1)/ 2 , where k natural. Yes it is
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