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Solve the following by substitution: y = x 5x = 12y
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it's a false expression
why?
coz you get 5y=12y which is false or just zero
I said it was 0,0 and I got it wrong
hmm, try using Cramer's rule
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lets say x-y=0 5x-12y=0 then\[\left[\begin{matrix}1 & -1 \\ 5 & -12\end{matrix}\right]\left(\begin{matrix}x \\ y\end{matrix}\right)=\left(\begin{matrix}0 \\ 0\end{matrix}\right)\]
dam nikga nd i got it wrong lol.......
Ax=b\[x=A ^{-1}*b\]
my teachz dum
lol
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\[\left(\begin{matrix}x \\ y\end{matrix}\right)=\left(\begin{matrix}0 \\ 0\end{matrix}\right)\]
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