Question

Jose has $2.50 in nickels and dimes in his jar. If he has 11 more nickels than dimes, how many dimes does he have?

Answer 1

Let d= the number of dimes; Let n= the number of nickels.

Since there are 11 more nickels than dimes then the number of nickels is 11+d=n

The value of the number of dimes + the value of the number of nickels is equal to $2.50.

So we have this equation.

d(.10)+n(.05)=2.50

Substitution d+11 for n we get

d(.10)+(d+11)(.05)=2.50

Which gives us .1d+.55+.05d=2.50 Combining terms gives us

.15d+.55=2.50

Subtracting .55 from both sides gives us

.15d=1.95

Dividing both sides by .15 gives us

d=13 dimes.