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solve for x, where x is a real number √(7x-14)=√(x+15)
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\[\sqrt{7x-14}=\sqrt{x+15}\] First step square both sides! :)
which would eliminate th square roots.
square both sides.... 7x - 14 = x+15 7x -x = 15+14 6x = 29 x = 29/6
yeah square both sides and then simplify. and yes it would be invalid if for some value of x the whole thing under root becomes negative.
got it:) just had to make sure i was solving it correctly at the beginning.
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