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2x+3/x^2-9+x/x-3
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Solve it when 2x+3/x^2-9+x/x-3=0 ?
\[\frac{2x+3}{x^2-9}+\frac{x}{x-3}\]Is this what the problem looks like?
yes
Put the problem into common terms (common denominator), then simplify.
ok thanx
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\[\frac{2x+3}{x^2-9}+\frac{x}{x-3}=\frac{2x+3}{(x+3)(x-3)}+\frac{x}{x-3}=\frac{2x+3}{(x+3)(x-3)} +\frac{x}{x-3}\frac{x+3}{x+3}\]\[= \frac{x^2+5x+3}{(x+3)(x-3)}\]
The combination of the math and typing on this one had me going in circles.......
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