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OpenStudy (anonymous):
2xyz+8xy^2
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OpenStudy (nottim):
gess you can factor out 2 right?
OpenStudy (nottim):
Taht would make this 2(xyz+4xy^2) right?
OpenStudy (chriss):
x and one of the y's will factor as well.
OpenStudy (anonymous):
2xy(4y+z) xy(8y+2z) y(8xy+2xz) x=0 y=0
jimthompson5910 (jim_thompson5910):
You can also factor out xy as well, so the complete factorization is 2xy(z + 4y)
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OpenStudy (anonymous):
Ok! so either way will be correct
jimthompson5910 (jim_thompson5910):
Either 2xy(4y+z) or 2xy(z+4y) is correct
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