Question

The sum of two numbers is -33. One number is 3 more than twice the other. Find the larger of the two numbers.

Answer 1

x= first number
-33-x=second number
x=2(-33-x)+3

Answer 2

Solve tat and you'll have it.

Answer 3

would -12 be the answer?

Answer 4

Let x = first number
Let y = second number

x+y=-33
x=2y+3

So the larger number is 'x' because it's more than twice the value of 'y'.

Answer 5

yes. -12 would be the answer.

Answer 6

thanx

Answer 7

(2y+3)+y=-33
3y+3=-33
-3 -3
3y=-36
/3 /3

y=-12

Yep! :)

Answer 8

What about this problem

Answer 9

Find two numbers whose sum is 42 and whose difference is 16.

Answer 10

yw

Answer 11

x+y=42
x-y=16

Answer 12

Add the two equations to eliminate y and solve for x

Answer 13

would it be 13 and 23?

Answer 14

???

Answer 15

If you add those two equations together, you get:
2x=58
/2 /2

x=29