consider 3 urns. urn A contains 2 white and 4 red balls, urn B contains 8 white and 4 red balls, and urn C contains 1 white and 3 red balls. If 1 ball is selected from each urn, what is the probability that the ball chosen from urn A was white given that exactly 2 balls were selected?

Question

consider 3 urns. urn A contains 2 white and 4 red balls, urn B contains 8 white and 4 red balls, and urn C contains 1 white and 3 red balls. If 1 ball is selected from each urn, what is the probability  that the ball chosen from urn A was white given that exactly 2 balls were selected?

pythagoras123 · Answer

2/9 probability

pythagoras123 · Answer

You see, there is a 2/6 chance of picking a white ball our of Urn A. There is a 2/3 chance of the person even drawing a ball from Urn A. Thus $$2/6\times2/3$$ is 2/9.