Question

Solve -3t + 6 < 3.
A. t < 5
B. t > 1
C. t > -5
D. t < -1
and


Solve 3(t - 2) > 4(2t + 11).
A. t > -10
B. t > 1.8
C. t < 1.8
D. t < -10
could you explain how you got the answer? i'm lost on this

Answer 1

-3t+6<3

Move all terms not containing t to the right-hand side of the inequality.
-3t<-3

Divide each term in the inequality by -3.
t>1

Answer 2

-3t + 6 < 3.
1. both sides -6
-3t + 6 -6< 3 -6
-3t < -3
2. Both sides divided by -3 (remember to change the sign)
-3t/-3 > -3/-3
t>1
Get it?

Answer 3

3(t-2)>4(2t+11)


3(t-2)>8t+44

move terms not containing t to the right side of the inequality.
-5t-6>44

Move all terms not containing t to the right side of the inequality
-5t>50

Divide each term in the inequality by -5.
t<-10

Answer 4

3(t - 2) > 4(2t + 11)
1. Expand the expression
3(t - 2) > 4(2t + 11)
3t - 3(2) > 4(2t) + 4(11)
3t -6 > 8t +44
2. both sides add 6
3t -6 +6> 8t +44 +6
3t > 8t +50
3. Both sides minus 8t
3t > 8t +50
3t-8t> 8t +50 -8t
-5t > 50
4. both sides divided by -5
-5t/-5 < 50/-5
t< -10
understand?