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Find all solutions to the equation. cos(Theta)-1=-1 Answer needs to be in radians in terms of pi
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is it \[\cos(\theta)-1=-1\]?
cos(theta) - 1 = -1 cos(theta) - 1+1 = -1+1 cos(theta) = 0 arccos(cos(theta)) = arccos(0) theta = pi/2 + 2pi*n or theta = 3pi/2 + 2pi*n theta = pi/2 + pi*n
same as \[\cos(\theta)=0\] so \[\theta =\frac{\pi}{2}+k\pi,k\in \mathbb Z\]
thanks, ya guys:)
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