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tossing a fair die is an experiment that can result in any integer number from 1 to 6 with equal probabilities .let X be the number of dots face of a die .compute E(x) and var(x)
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E(x)=3.5 in your head, since it is the average
\[\frac{1+2+3+4+5+6}{6}=3.5\]
What about when two dice is thrown? :) Not so much in head now :D
ffm can compute the variance, but probably need pencil and paper for this one
\[Var(X) =E(X^2)-(E(X))^2 \]
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Pencil + Paper or simply Mathematica ? ;-)
you can do it for two dice in your head too, it is 7, most likely roll
Wow sat! you are amazing :D
How do you did it?
@satellite73 Ping! waiting ...
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ok thank u :) now i can computer variance by myself.
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