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Mathematics 25 Online
OpenStudy (anonymous):

Suppose that the functions s and t are defined for all real numbers x as follows. s(x)=x+1 t(x)=4x+4

OpenStudy (anonymous):

Write the expressions for (s*t)(x), (s+t)(x), and evaluate (s-t)(-1)

OpenStudy (apoorvk):

t(x)=4(x+1).. basically 4 times s(x) so.. multiply (x+1)*4(x+1) for first part that is s*t add 'em for the second. and subtract them for the third and then put x=-1 to evaluate!! simple enough.. post what you get.

OpenStudy (anonymous):

first one= 4x^2+8x+4?

OpenStudy (apoorvk):

ja!!! :) next two??

OpenStudy (anonymous):

5x+5?

OpenStudy (anonymous):

3x-3?

OpenStudy (anonymous):

-3x-3...

OpenStudy (anonymous):

wait lol.. :/

OpenStudy (apoorvk):

Rightie-right....!! (-3x-3 would be right you noticed it good) but, you must put x=-1 in the last part as that is what they have asked you to evaluate

OpenStudy (anonymous):

go with the -3x-3

OpenStudy (anonymous):

so now I do (-3x-3)(-1)?

OpenStudy (anonymous):

no, substitute -1 for the x

OpenStudy (anonymous):

crap i cant type -3(-1)-3? 3-3 =0

OpenStudy (anonymous):

looks good to me

OpenStudy (apoorvk):

yeha thats it... its would be '0'.. you did it!! c'mon ma, have a bit of confidence.. you are doing it alright!!

OpenStudy (anonymous):

thank you!

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