Suppose that the functions s and t are defined for all real numbers x as follows.
s(x)=x+1
t(x)=4x+4
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OpenStudy (anonymous):
Write the expressions for (s*t)(x), (s+t)(x), and evaluate (s-t)(-1)
OpenStudy (apoorvk):
t(x)=4(x+1).. basically 4 times s(x)
so.. multiply (x+1)*4(x+1) for first part that is s*t
add 'em for the second.
and subtract them for the third and then put x=-1 to evaluate!! simple enough.. post what you get.
OpenStudy (anonymous):
first one= 4x^2+8x+4?
OpenStudy (apoorvk):
ja!!! :) next two??
OpenStudy (anonymous):
5x+5?
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OpenStudy (anonymous):
3x-3?
OpenStudy (anonymous):
-3x-3...
OpenStudy (anonymous):
wait lol.. :/
OpenStudy (apoorvk):
Rightie-right....!! (-3x-3 would be right you noticed it good) but, you must put x=-1 in the last part as that is what they have asked you to evaluate
OpenStudy (anonymous):
go with the -3x-3
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OpenStudy (anonymous):
so now I do (-3x-3)(-1)?
OpenStudy (anonymous):
no, substitute -1 for the x
OpenStudy (anonymous):
crap i cant type -3(-1)-3? 3-3 =0
OpenStudy (anonymous):
looks good to me
OpenStudy (apoorvk):
yeha thats it... its would be '0'.. you did it!!
c'mon ma, have a bit of confidence.. you are doing it alright!!
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