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okay:move the y's to one side and on the other
so you get y-y^7=5x^2
when you derive you replace y with dy/dx, and derive everything else regularly, so, dy/dx-10x=7y^6dy/dx solve for dy/dx -10x=-dy/dx+7y^6dy/dx -10x/(-1+7y^6)=dy/dx hope that helps
then dy/dx the entire equation:
the 5x^2 becomes 10x
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the y becomes just y' and y^7 becomes 7y^6y'.
then pull out a y' . so you have y'(7y^6-1)
wouldnt the y' become dy/dx?
then just move that whole parenthesis to the other side and you have your answer:)
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