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8^(y - 2) = 2^y
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y=3
This was just using my brain, sorry.
I know you set the bases equal, then put the extra numbers to distribute to the powers, then set the powers equal.
8^(y - 2) = 2^y (2^3)^(y - 2) = 2^y 2^3(y - 2) = 2^y 3(y - 2) = y now solve...
Yep ;P What he did.
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