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y+3=2/5(x+9) write this equation in standard form PLEASE HELP
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standard form= Ax+By=C
first you want to distribute by using distributive property
Nah.. isn't it Ax+By+C=0? y+3=2/5(x+9) y+3 = (2/5)x + (2/5)(9) Both sides x5 5y +15 = 2x + 18 Swap the terms 2x+18 -(5y+15) =0 2x - 5y +3 =0
It is actually Ax + By = C. Ax(^2) + By + C = 0 is more for quadratic equations.
Okay, thanks
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Standard Form: the standard form of a line is in the form Ax + By = C where A is a positive integer, and B, and C are integers.
So, 2x - 5y = -3
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