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Let x = ln(root4(13)) Then x = A ln(B) where B is an integer what is a and b?
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use ln(a^b) = b ln(a)
ok do i need to take out of the 4root?
\[\sqrt{x} = x^{1/2}\]
yes you need to have an expression that look like Aln(B)
but since its to the 4 root would it be 13^1/4?
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yep that's it
so a =1/4 b= 13
yes
to the 1/3?
nevermind
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thanx again
you're welcome. what do you mean by to the 1/3 ?
i meant 1/4ln13^1/3
i subtracted 1 from 1/4
1/4-1
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1/4*ln 13^1/3 = 1/4 *1/3 * ln 13 = (1/12) *ln 13
(not very sure i m answering you're question ^^)
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