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Let T : C∞(R) −→ C∞(R) be the map given by T(f) = f′′− 2f′− 3f . Find a linear combination a sin(x) + b cos(x) which solves the equation f′′− 2f′− 3f = 2 cos(x).
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\[f(x)=c_1e^{2x}+c_2+\frac{1}{10}(-15x-8\sin(x)-4\cos(x))\]
how did you get that!!!!!
I solved the ODE you posted.
and how is that equal to 2cosx?
If you take that function and evaluate\[f''-2f'-3f,\]you will get\[2\cos(x).\]
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hmm ok
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