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what is the first step in solving 2^x=4^(x+1)
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4=2^2 right?
yea
\[2^x=2^{2(x+1)}\]
so bases are the same so set exponents = and solve for x
so the first step would be to set thebases = to eachother
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Yes if you can First step is to try to see if you can write the expressions on both sides so they have the same base
thank u so much
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