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Condense the expression: log (base 3) 2x + 3 log (base 3) 4x Please show work! Thank you ^_^
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\[\log_{3} (4x(2x+3))\] \[\log_{a} MN=\log_{a}M+\log_{a}N\]
\[\log_{2} (x+8)=4\]Thanks :) how do i do this one?
whoa luis don't know what you did there but that's not right
it's right; that is the answer my teacher got.
all the work is right except how u got to the first line
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oh i didn't see the 3 before the log in the 2nd part, my bad, you are right
log base 2 ? On both sides?
for the 2nd one, put it into exponential form. 2^4=x+8
Thank you. (:
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