Question

Use the quadratic formula to find the zeros of the function y = 2x2 + 3x + 6. Round to the nearest tenth if necessary.

Answer 1

2x2 + 3x + 6
a=2, b=3 , c=6
\[x=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a}\]

Answer 2

this is what you should have, but idk bout the -39 in the square root but overall this should be correct