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The measure of each interior angle is twice the measure of an exterior angle, how may sides does the regular polygon have?
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The sum of the exterior angles of a regular polygon is 360. If the polygon has n sides, each exterior angle is 360/n. The problem says that the interior angle is twice the exterior angle but the interior angle is supplementary to the exterior angle. So the interior angle is 180-360/n. And so:
\[2(\frac{360}{n})=180-\frac{360}{n}\]
n is the number of sides, by the way.
In the regular polygon, an interior angle and an exterior angle form a linear pair.|dw:1332877003562:dw|
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