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Ok can someone give me the anwser to this so i will understand?! :) Solve the equation for x: 3x2 = 6x
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\[3x^2-6x=0\] is a start
now factor as \[3x(x-2)=0\]
set each factor equal to zero and solve \[3x=0\implies x=0\] \[x-2=0\implies x=2\] clear or need more explanation?
i think i get it. so the anwser would be 2?
and 0
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yes there are two answers since your original equation started with an \[x^2\]
and you can check them both you started with \[3x^2=6x\] if you replace x by 0 you get \[0=0\] so you know that one works
then if you replace x by 2 you get \[3\times 2^2=6\times 2\] \[12=12\] so that one works as well
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