Question

Find the vertex of the parabola formed by the following quadratic function: y = 2x2 – 8x + 2

a. (-4, 66)

b. (4, 2)

c. (-2, 26)

d. (2, -6)

Answer 1

(2,-6)

Answer 2

when you get the equation in std form, the x-coordinate of the vertex can be found by the following formula
\[x=\frac{-b}{2a}\]where your quadratic is\[y=ax^2+bx+c\]

Answer 3

Oh ,, okay thanks , so thats the formual i have ta use when finding the vertex ?

Answer 4

It just gives you the x-coordinate of the vertex. To get the y-coordinate, plug the value of x you got back into the equation of the parabola. You only use this formula when the equation is given in the y=ax^2+bx+c form.

Answer 5

Find the vertex of the parabola formed by the following quadratic function: y = 7x2 + 21x – 1
Question 3 answers

a. (-2, -15)

b. (2, 69)

c. (1, 27)

d. (-3/2, -67/4)

Answer 6

ok, your turn

Answer 7

Vertex of y=ax^2+bx+c is \( \large \left(\frac{-b}{2a}, \frac{-b^2+4ac}{4a} \right)\)