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√48x^6=I need help doing this please.
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what are the factors of 48?
1,2,3,4,6,8,12,16,24,48
yes, I'm sorry, I meant can you factor it? 2,2,2,2,3 isn't it?
so you have the square root of (2 2 2 2 3 x x x x x x) right?
yes.
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\[\sqrt{48x^6}=\sqrt{2^4*3}\sqrt{x^6}=4x^3\sqrt{3}\]
so pull out as many pairs as you can, and see what is left
animal is right, but I think he used magic
so i got two sets of 2s and i set of 3xs. so that is 4(x^3)?
exactly
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okay. thank you for your help.
but dont forget what is left over stays under the radical
so the 3 goes under the radical?
can you help me with another one? a cube root?
yep, can't pull it out so it hangs around out there
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