Question

How do you restrict the domain of h(x) = 3(x+2)^2-1 so that h^-1 would be a function?

Answer 1

\[h(x)=3(x+2)^2-1\] has vertex at
\[(-2,-1)\] and is a parabola that opens up, so it is decreasing on
\[(-\infty,-2)\] and increasing on
\[(-2,\infty)\]

Answer 2

to make it one to one make sure it is always decreasing or increasing. so you can pick either interval above

Answer 3

what does that symbol mean?

Answer 4

inifinity \[\infty\]

Answer 5

ty

Answer 6

and how would you write that as a restriction?

Answer 7

\[x\geq -2\] would work