Which value(s) of x should be excluded for the polynomial? x^2-16/x^2-6x+9

A. 3
B. 3 and -3
C. 4
D. 4 and -4

Question

Which value(s) of x should be excluded for the polynomial? x^2-16/x^2-6x+9

	A.	3
	B.	3 and -3
	C.	4
	D.	4 and -4

anonymous · Answer

I think it's D

istim · Answer

Why excluded?

anonymous · Answer

wat do u mean?

istim · Answer

Actually, just ignore me. Someone else, help!

anonymous · Answer

you can never divide by 0
so where will there be a problem with this one?

anonymous · Answer

it's A- (3)

anonymous · Answer

because???

anonymous · Answer

ik how did u get tht?

anonymous · Answer

he is wrong, by the way

anonymous · Answer

okay so then wat is it philip

anonymous · Answer

you cannot divide by zero, so what values for x will cause problems here? 
that is the question

anonymous · Answer

what is the denominator? and when is it 0?

anonymous · Answer

sorry, forgot to ask, do you want to learn this stuff or just want to fill in some homework? I am ok with it either way.

anonymous · Answer

look
Factorize them (x^2-16)/(x^2-6x+9)
so
(x^2-16) = (x-4)(x+4)
(x^2-6x+9)=(X-3)(x-3)
therefore
(x-4)(x+4)/(x-3)(x-3)
since any   denominator makes the whole equation undefined
Therefore the no. 3 is Refused
i mean Answer (A)

anonymous · Answer

fill in sum homework but kind of want to know a little about it.

anonymous · Answer

i mean when the denominator=0
the whole equation is undefined

anonymous · Answer

yep, that's right. I was mistaken.
appologies where appropriate

anonymous · Answer

okay thnk u jop and philip u guys helped aa lot