Find the equation of the line that contains the point (4, 3) and is perpendicular to the line y = (3/4)x − 3.
what is the slope of the line given?
this is the question right off my assignment.
what is there is what I have to work with
ok, what is the slope of y = (3/4)x - 3?
so am I taking the (3/4)*4, o am I needing to flip it?
the slope is 3/4 y = m x + b m is the slope so what is the negative reciprocal of 3/4?
4/3
almost... have to negate it too
yea sorry
negative means change the sign, reciprocal means flip it and that is so much mess, they just say "inverse" and inverse gets very important a couple years from now in your math studies
ok so its -4/3
anyway, the slope of the perpendicular line is -4/3 so all we need now is the y intercept so here is where you plug your point into y = -4/3 x + k and solve for k
ok which I get 3=-5 1/3 + k?
yes, but you have to solve for k
8 1/3
yes, but they don't usually come out like that but when they do, 25/3 is better
so use that k in y = -4/3 x + k and you should have the right answer
ok thank you so much
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