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y intercept = -1 x intercept = ln(1/2)/ln(3) asymptote => x = -1
yea ... yea
take limit x->inf and limit x->-inf if it converges, or has a limit than that is your asymptote ... and sorry about wrong asymptote ... the asymptote is y = -1 not x = -1
it's not in the graph ... as x tends to - infinity ... y tends to -1 ,, so y = -1 must be your asymptote
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no, as you decrease the value of x ... to negative infinity, y -> -1 http://www.wolframalpha.com/input/?i=asymptote+y+%3D+2+*+3%5Ex+-+1
just what might be the value of y =2(3^-10) − 1 ... the more you decrease x, y comes closer to -1
no, you decrease x, x=-1,-2,-3, ...-100, .... -10000 and y comes closer to -1
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