Question

x^2-6x=9?
5x^2=6+2x?
x^2=4x+21?
3x^2+2x=3?
I am trying to solve for x and I don't know how to solve these quadratic equations.

Answer 1

ALL TOGTHER ?

Answer 2

no each one is a seperate problem

Answer 3

OK

Answer 4

FOR equatiom # 3 :
x^2-4x-21=0
(x-7)(x+3)=0
then x=7 and x=-3

Answer 5

i think x=1 on the last question but im not sure

Answer 6

ok wait iam try :)

Answer 7

thank you

Answer 8

\[x=(1+\sqrt{10})\div 3 and x=(1-\sqrt{10})\div3\]
for last one

Answer 9

i solve it by The general law ..