if f(x) is an antiderivative of x*e^-x^2 and f(0)=1 then f(1)=
a. 1/e
b. 1/2e-3/2
c. 1/2e-1/2
d. -1/2e+3/2
e. -1/2e+1/2

Question

if f(x) is an antiderivative of x*e^-x^2 and f(0)=1 then f(1)= 
a. 1/e
b. 1/2e-3/2
c. 1/2e-1/2
d. -1/2e+3/2
e. -1/2e+1/2

anonymous · Answer

Use the equation plzz I can't understand it

anonymous · Answer

what do you mean use the equation?

anonymous · Answer

There is an equation option below to write it as an equation using mathematical signs

anonymous · Answer

$$xe ^{-x ^{2}}$$

anonymous · Answer

you need to just calculate the derivative of the function (because its the anti derivitve of f(x) so diverentiating gets you back to f(x) which is what the value for is asked) and input 1

anonymous · Answer

If it is $$x*e^(-x^2) $$ then the answer is -1/(2e)+3/2

anonymous · Answer

thanks!