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sigma notation
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\[\sum_{n=1}^{50} 3n\]
need someone to explain how to do this
that is the sum of 50 numbers the first number is 3(1) = 3 then 3(2) = 6 then 3(3) = 9 and so on to 3(50) = 150 so it is the sum of 3 + 6 + 9 + ... + 150
isn't there a formula, so u wouldn't have to go all the way up to 50 ?
maybe, but my brute force script just told me it was 3825 sometimes computers are useful
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\[\sum_{n=1}^{82} 2(n-1)\]
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