I need help with calculus.
i need to find the volume of the solid generated by revolving region bounded by the graphs of the equations about the x-axis.
y= 1/(square root of x+1) , y=0 x=0 and x=3

Question

I need help with calculus. 
i need to find the volume of the solid generated by revolving region bounded by the graphs of the equations about the x-axis. 
y= 1/(square root of x+1) , y=0 x=0 and x=3

anonymous · Answer

i'm not sure what the radius would be.

anonymous · Answer

you have to graph it to find the radius, usually it is called "x" and then we call height the y output values which is the long equation y=_____________ you gave. from there we have and area equation. then we know that the volume is just the integral of the area function from some a to b (that you set by looking at the graph)

anonymous · Answer

would the interval be from 0 - 1 or 0-3? if its revolving around "x"

anonymous · Answer

check this out real fast man it is very helpful and direct! http://tutorial.math.lamar.edu/Classes/CalcI/VolumeWithCylinder.aspx

anonymous · Answer

walks throught the steps!