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OpenStudy (mani_jha):
How to solve the following equation? Or at least tell me how many real solutions it has:
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OpenStudy (mani_jha):
\[4\sqrt{4-x ^{2}}+3x=-20\]
OpenStudy (experimentx):
sorry ... second degree equation .. just separate the root on one side and square
OpenStudy (mani_jha):
Oh yeah..that didn't come to my mind. Thanks!
OpenStudy (anonymous):
4 sqrt(4-x^2) = -20-3x 16( 4-x^2) = 400+120x+9x^2 64-16x^2 = 400 +120x +9x^2 25x^2+120x+336=0 b^2 -4ac = 120^2 - 4(25)(336) <0 therefore, no real solution
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